Question

The equilibrium constant for a reaction is 10. What will be the value of ΔG°? R = 8.314 JK^-1 mol^-1, T = 300 K

Answer 1

ΔG° = -2.303 RT log Kc

= -2.303 x (8.314 mol^-1 K^-1) x 300 K log 10

= -2.303 x 8.314 x 300 x 1

= -5527 J mol^-1

= -5.527 kJ mol^-1