Let A(3, 0), B(- 2, 2) and C(8, 2) be the given points Using two-point form, we can find the equation of AB as
y - 0 = (- 2 - 0)/(- 2 - 3)(x - 3)
⇒ y = 2/5(x - 3)
⇒ 5y = 2x - 6 ....(1)
If C(8, 2) lies on the line (1) then we can conclude A, B and C are collinear.
Now putting x = 8 and y =2 in (1), we get
5(2) = 2(8) – 6
10 = 16 – 6= 10
10 – 10 = 0
= Clieson(1)
= A, B and C are collinear