Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Mathematics by (55.1k points)

Differentiate the following with respect to x

(i) y = (ax)m + bm

(ii) y = x3 + 4x2 + 7x + 2

1 Answer

+1 vote
by (52.8k points)
selected by
 
Best answer

(i) y = amxm + bm

dy/dx = ammxm-1 + 0 = ammxm-1

(ii) dy/dx = 3x2 + 4(2x) + 7 = 0

= 3x2 + 8x + 7

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...