Question

Prove that ∫f(x).dx, x ∈ [0, b] = ∫f(a + b - x) dx, x ∈ [a, b] and hence. Evaluate ∫1/1+√tanx dx, x ∈[π/3, π/3]

Answer 1

let t = a + b – x then dt = -dx

when x =a and x = b

t = b t = a

f(x) is continuous, find the value of k.