∫(sin x dx/(sin x + cos x)), x ∈ [0,π/2]
Let I = ∫(sin x/(sin x + cos x)) dx, x ∈ [0,π/2] ...(i)
I = ∫(sin((π/2) - x)/(sin((π/2) - x) + cos((π/2) - x)) dx, x ∈ [0,π/2]
I = ∫(cos x/cos x + sin x)) dx, x ∈ [0,π/2] ...(ii)
Adding eq. (i) and (ii),
2I = ∫((sin x + cos x)/(sin x + cos x)) dx, x ∈ [0,π/2]
2I = ∫1.dx, x ∈ [0,π/2]
2I = [x], x ∈ [0,π/2]
2I = (π/2) - 0
I = π/4