Total letters = 11, I = 4, S = 4, P = 2.
∴ The total number of permutations 7
4s’s are together can be taken as 1 unit i.e.
M |
I |
SSSS |
P |
Total |
1 |
4 |
1 |
2 |
8 |
∴ The number of permutations = 8!/(4! x 2!)
(b) 4s’s are not together = Total number of ways – 4s’s are together
= 11!/(4! x 4! x 2!) - 8!/(4! x 2!) (C)
Begin with MISS: The remaining 7 letters can be arranged in 7!/(3! x (2!)2)
(d) Begin with SIP: The remaining 8 letters (I = 3, S = 3) can be arranged in 8!/3!2