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Evaluate : ∫x/(1 + sin x) dx, x ∈ [0,π]

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Evaluate : ∫x/(1 + sin x) dx, x ∈ [0,π]

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Adding eq. (i) and (ii),

2I = π∫(1 - sin x)dx/cos2x, x ∈ [0,π]

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