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Find the middle term in the expansion of (2x^2/3 - 3/2x)^10

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Find the middle term in the expansion of (2x2/3 - 3/2x)10

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Identifying middle term as T6

Tr + 1 = 10Cr(2x2/3)10-r(-3/2x)r

Substituting r= 5 and simplifying to get T6 = -252x5 .

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