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For the equilibrium, PCl5 (g) ⇌ PCl3 (g) + Cl2 (g) at 298 K, K = 1.8 × 10^-7.

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For the equilibrium, PCl5 (g) ⇌ PCl3 (g) + Cl2 (g) at 298 K, K = 1.8 × 10-7. Calculate ΔG° for the reaction (R = 8.314JK-1mol-1)

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1 Answer

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by (49.7k points)
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Best answer

PCl5(g) ⇌ PCl2(g) + Cl2(g), K = 1.8 × 10-7 

ΔG° = -2.303 RTlogK = -2.303 × 8.314 JK-1mol-1 × 298K × log(1.8 × 10-7) 

= -2.303 × 8.314 × 298[log 1.8 + log10-7] = -19.147 × 298 [0.2553 – 7.000]

equilibrium

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