If the coin is to revolve with the record then the force of friction must be enough to provide the necessary centripetal force.
i.e. mr ω2 ≤ µsmg or r ≤ \(\frac{μsg}{ω^2}\)
Here, ω = 33 \(\frac {1}{3}\)rpm

The coin placed within the radial distance of 0.12 m will revolve with the record. Hence coin at 4 cm will revolve with the record.