Question

MnO₄ + H₂C₂O₄ → Mn²⁺ + CO₂ in acid solution by ion electron method.

Answer 1

For MnO₄^- + H₂C₂O₄ → Mn²⁺ + CO₂;

here

∴ 5e^- + MnO₄^- → Mn²⁺ + 4H₂O

and 8H⁺ + 5e^- MnO₄^- → Mn²⁺ + 4H₂O    ....(i)

In H₂C₂O₄ → CO₂

here

∴ H₂C₂O₄ → 2CO₂ + 2e^-

H₂C₂O₄ → 2CO₂ + 2H⁺ + 2e^-  ...(ii)

Multiplying equation (i) by 2 and (ii) by 5 and adding (i) and (ii)

2MnO₄^- + 6H⁺ + 5H₂C₂O₄ → 10CO₂ + 2Mn²⁺ + 8H₂O