Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
734 views
in Chemistry by (62.4k points)

Write the redox reactions using half equations.

2Fe3+(aq) + 2e(aq) → I2(s) + 2Fe2+(aq)

In the reactions given above, mention 

(i) Which reactant is oxidized? To what ?

(ii) Which reactant is the oxidizer?

(iii) Which reactant is reduced? To what?

(iv) Which reactant is the reducer?

1 Answer

+1 vote
by (64.8k points)
selected by
 
Best answer

2Fe3+ + 2e → 2Fe2+ (reduction), 

2l → I2 +2e (oxidation) 

Fe3+ is reduced to Fe2+

I is oxidized to I2

I is the reducer 

Fe3+ is the oxidizer.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...