Question

Three identical capacitors C₁, C₂ and C₃ have a capacitance of 1.0μF each and they are uncharged initially. They are connected in a circuit as shown in the figure and C₁ is then filled completely with a dielectric material of relative permittivity ∈_r. The cell electromotive force (emf) V₀ = 8V. First the switch S₁ is closed while the switch S₂ is kept open. When the capacitor C₃ is fully charged, S₁ is opened and S₂ is closed simultaneously. When all the capacitors reach equilibrium, the charge on C₃ is found to be 5μC. The value of ∈_r.

Answer 1

Answer [1.50]

solution:-

When S₁ was closed charge on C₃ = q₃ = 1 × 8
= 1 × 10^–6 × 8 = 8 μC
After closing of S₂

Comments

Could you explain how you got charge on c3

Answer 2

Answer: 1.50

Applying loop rule