Question

The acceleration of a particle executing SHM Is 20ms^-1 at a distance of 5 m from the mean position. Calculate its time period and frequency.

Answer 1

a = 20m/s², y = 5m.

We know that a = | ω² y|

= 2 rad/s or 2πf = 2

Frequency f = \(\frac{2}{2 \times 3.14}\) = 0.3185 Hz

Period T = \(\frac{1}{f}\) = \(\frac{1}{0.3185}\) = 3.14s