Here, N= 50; Range = H.V.-L. V. = 49-12 = 37
The number classes as per Sturge’s rule are obtained as follows:
Number of class intervals (K) = 1 + 3.322 logN = 1 + 3.22 log 50 = 1 + (3.22 × 1.6990) = 6.47 = 7
classes (Approx.) Size/width of class intervals – e = Range/Number of class intervals) = 37/7
5.28 = 6 (Approx.)
The size/width of each class is 6 and there are 7 classes. Thus, the required continuous frequency distribution with exclusive class intervals width is prepared as :
Frequency distribution of marks of students
![](https://www.sarthaks.com/?qa=blob&qa_blobid=4529454964539119682)