Question

Calculate the spin only magnetic moment of Fe²⁺.

Answer 1

Fe²⁺ ion has electric configuration (Ar)4S⁰3d⁶ it has four paired electrons 

∴ n = 4 

spin only magnetic moment μ = \(\sqrt{n(n+2)}BM\)

= \(\sqrt{4(4+2)}BM\) 

= \(\sqrt{24}BM\) 

= 4.9BM