Question

Differentiate the function with respect to x: \(tan^{-1}{\frac{\sqrt{1 + a^2x^2} - 1}{ax}}\), x ≠ 0

Answer 1

Given \(tan^{-1}{\frac{\sqrt{1 + a^2x^2} - 1}{ax}}\)

Suppose y = \(tan^{-1}{\frac{\sqrt{1 + a^2x^2} - 1}{ax}}\)

On differentiating with respect to x