Question

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 x 10¹⁰ Hz and amplitude 48 V m^-1.
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average energy density of the B field, [c = 3 x 10⁸ ms^-1]

Answer 1

u = 2 x 10¹⁰Hz

E₀ = 48 Vm⁴ C

= 3 x l0⁸ms^-1