PV = nRT
Given P = 150 KPa = 150 × 103 Pa, V = 150 cm3 = 150 × 10–6 m3, T = 300 k


= 779.422 × 103 Pa ≈ 780 KPa
(d) ΔQ = W + ΔU or W = –ΔU [ΔU = 0, in adiabatic]
= – nCVdT = – 0.009 × 16.6 × (520 – 300) = – 0.009 × 16.6 × 220 = – 32.8 J ≈ – 33 J
(e) ΔU = nCVdT = 0.009 × 16.6 × 220 ≈ 33 J