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Draw the circuit diagram and explain the working of CE amplier. Also mention any two applications.

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The power supply Vcc, resistors R1, R2, Rc and RE provide required DC bias for the transistor, C1 and C2 are blocking capacitors which allow ac and block dc. The bypass capacitor CE bypass es ac at the emitter to ground.

During positive half cycle at the input signal, forward bias on the emitter base junction increases. Hence the currents ib and ic increase. As a result, ic R increases and V decreases because VCE = VCC - icRc

Thus we get negative half cycle at the output. During negative half cycle of input signal, forward bias on the emitter junction decreases. Hence ib, ic decrease and icRc also decreases. As VCB = VCC – icRc , VCE increases.
Thus, we get positive half cycle at the output.
Thus a phase shift of 180° exists between the input and the output.
Applications: It is used as AF amplifier, RF amplifier and signal generator.

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