Marks scored by the students is a normal variable with the parameters.
µ = 80, σ = 5.
Then S.N.V:
(i) p(marks more than 90)
=p(x > 90) = p(z) >
p(z > 2) = Area from 2 to ∞
from the table = 0.0228
(ii) p(marks between 70 and 85) =p(70 <x< 85)
= Area tray (-2) to 1
= Area tray (-2) to ∞ – Area tray 1 to h
= 0.9772 – 0.1587 = 0.8185.