Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.5k views
in Statistics by (62.7k points)

Marks scored by the students of a class follow normal distribution with mean 80 and S.D.5. Find the probability that a student selected at random from the class scored: 

(i) More than 90 marks 

(ii) Between 70 and 85 marks.

1 Answer

+2 votes
by (57.2k points)
selected by
 
Best answer

Marks scored by the students is a normal variable with the parameters. 

µ = 80, σ = 5. 

Then S.N.V:

(i) p(marks more than 90) 

=p(x > 90) = p(z) > \frac{90-80}{5}
p(z > 2) = Area from 2 to ∞
from the table = 0.0228

(ii) p(marks between 70 and 85) =p(70 <x< 85)

= Area tray (-2) to 1
= Area tray (-2) to ∞ – Area tray 1 to h
= 0.9772 – 0.1587 = 0.8185.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...