We have,
cos θ = \(\frac{4}{5}\)
And we know that,
sin θ = √(1 – cos2 θ)
⇒ sin θ = √(1 – (\(\frac{4}{5}\))2)
= √(1 – (\(\frac{16}{25}\)))
= √[\(\frac{(25 \,–\, 16)}{25}\)]
= √(\(\frac{9}{25}\))
= \(\frac{3}{5}\)
∴ sin θ =\(\frac{3}{5}\)
Since,
cosec θ = \(\frac{1}{sin\, θ }\)
= \(\frac{1}{(3/5)}\)
⇒ cosec θ = \(\frac{5}{3}\)
And, sec θ = \(\frac{1}{cos θ }\)
= \(\frac{1}{(4/5)}\)
⇒ cosec θ = \(\frac{5}{4}\)
Now,
tan θ = \(\frac{sin θ}{cos θ }\)
= \(\frac{(3/5)}{(4/5)}\)
⇒ tan θ = \(\frac{3}{4}\)
And, cot θ = \(\frac{1}{tan θ}\)
= \(\frac{1}{(3/4)}\)
⇒ cot θ = \(\frac{4}{3}\)