Question

If K₁, K₂, K₃ are equiliberium constant for formation of AD, AD₂, AD₃ respectively as follows A + D ⇋ AD, AD + D ⇋ AD₂, AD₂ + D ⇋ AD₃. Then equilibrium constant 'K' for A + 3D ⇋ AD₃ is related as

(a) K₁ + K₂ + K₃ = K

(b) log K₁ + log K₂ + log K₃ = log K

(c) K₁ + K₂ = K₃ + K

(d) log K₁ + log K₂ = log K₃ + log K

please provide the answer with solution

Answer 1

The correct answer is (b) 

A + D ⇌ AD........k₁

AD + D ⇌ AD₂.....k₂

AD₂ + D ⇌ AD₃....k₃

By adding all eqn we get,

We know that 
\(k_1\times k_2\times k_3=k\)

So we have 

log k₁ + log k₂ + log k₃ = logk