Given as ∫cos mx cos nx dx, m ≠ n
As we know that 2cos A cos B = cos (A - B) + coa (A + B)
On substituting the above formula, we get
So, cos mx cos nx = (cos(m - n)x + cos (m + n)x)/2
So, the equation becomes,
As we know that a2 - b2 = (a + b) (a - b)
On substituting the above formula and satisfying, we get