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Each of the capacitors shown in figure (31-E6) has a capacitance of 2μF. Find the equivalent capacitance of the assembly between the points A and B. Suppose, a battery of emf 60volts is connected between A and B. Find the potential difference appearing on the individual capacitors.

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∴ C = 2μF
∴ In this system the capacitance are arranged in series. Then the capacitance is parallel to each other.
(a) ∴ The equation of capacitance in one row

C = C/3

(b) and three capacitance of capacity C/3 are connected in parallel

∴  The equation of capacitance

C = C/3 + C/3 + C/3 = C = 2μF

As the volt capacitance on each row are same and the individual is

= Total/N0. of capacitance = 60/3 = 20v

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