Question

Find the equation of the diameter of the circle 2x² + 2y² + 3x – 5y – 1 = 0 which when produced passes through the point (-1,2).

Answer 1

Given 2x² + 2y² + 3x – 5y – 1 = 0 & p = (-1,2)

Equation of the diameter with p(-1 ,2), & m = -3. 

y – y₁, = m(x – x₁); y – 2 = -3(x + 1); y – 2 = -3x – 3; 3x + y + 1 = 0.