Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.0k views
in Circles by (65.6k points)

Find the length of the chord of the circle x2 + y2 – 6x + 15y – 16 = 0 intercepted by the x-axis.

1 Answer

0 votes
by (65.3k points)
selected by
 
Best answer

Given x2 + y2 – 6x + 15y – 6 = 0 

C = \((3, \frac{-15}{2})\) & c = -16 

Length intercepted by x – axis = 2\(\sqrt{q^2 - c}\) 

\(= 2\sqrt{(3)^2 - (-16)}\) = 2\(\sqrt{9 + 16}\) = 2√25 = 10

∴ Length = 10 units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...