Question

Find the length of the chord of the circle x² + y² – 6x – 4y – 12 = 0 on the coordinate axes.

Answer 1

Given x² + y² – 6x – 4y – 12 = 0 

C = (3, 2) C = -12 

Length intercepted by x-axis \(2\sqrt{q^2 - c} \) = 2\(\sqrt{9 + 12}\)= 2√21 units 

Length intercepted by y-axis = \(2\sqrt{f^2 - c}\) = \(2\sqrt{4 + 12}\) = 2√16 = 8 units.