Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.1k views
in Circles by (65.6k points)

Find k such that the line x – 2y + k = 0 touches the circle x2 + y2 + 3x – 2y + 2 = 0.

1 Answer

+1 vote
by (65.3k points)
selected by
 
Best answer

Here centre (-\(\frac{3}{2}\), 1), r = \(\sqrt{\frac{9}{4} + 1 - 2}\) = \(\frac{5}{4}\)

r = length of perpendicular from \((-\frac{3}{2}, - 1)\) to the line x – 2y + k = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...