Let us consider the LHS:
1 - (sin2 x/(1 + cot x)) - (cos2 x/(1 + tan x))
On using the formula,
tan θ = sin θ/cos θ;
cot θ = cos θ/sin θ
Then,

On using the formula, a3 + b3 = (a + b) (a2 + b2 – ab)

As we know, sin2 x + cos2 x = 1.
1 – 1 + sin x cos x
sin x cos x
= RHS
∴ LHS = RHS
Thus proved.