(i) 1, 3, 9, 27
d = a2 – a1 = 3—1
d = 2 d = a3 – a2
d = 6
Here ‘d’ not is constant
∴ Given set of numbers do not form an A.P.
(ii) a, 2a, 3a, 4a
a1 = a
a2 = 2a
d = a2 – a1 = 2a - a
d = a
d = a3 – a2 = 3a - 2a
d = a
Here d’ is constant.
∴ Given set of numbers form an A.P.
Further three terms are :
4a + a = 5a
5a + a = 6a
6a + a = 7a
∴ Next three terms are: 5a, 6a, 7a.
(iii) a, a2 , a3 , a4
a1 = a. a2 = a2
d = a2 – a1 = a2 – a
d= a(a – 1)
d = a3 – a2 = a3 – a2
d = a2 (a – 1)
Here ‘d is not constant.
∴ Given set of numbers do not form an A.P.
(iv)

Here d’ is constant.
∴ Given set of numbers form an A.P.
Succeeding three terms are :

Here ‘d is not constant.
∴ Given set of numbers do not form an A.P.
(vi) 11,32,52, 72, …………
1, 9, 25, 49, ………….
a1 = 1, a2 = 9
d = a2 – a1 = 9 – 1
d = 8
d = a3 – a2 = 25 – 9
d = 16
Here ‘d’ is not constant,
∴ Given set of numbers do not form an A.P.
(vii) 11 , 52 , 72 , 73, ……….
1, 25. 49, 73, ……….
a1 = 1. a2 = 25, a3 = 49, a4 = 73
d = a2 – a1 = 25 – 1
d = 24
d = a3 – a2 = 49 – 25
d = 24
d = a4 – a3 = 73 – 49
d = 24
Here ‘d’ is constant.
∴ Given set of numbers form an A.P.
Succeeding three terms are:
73 + 24 = 97
97 + 24 = 121
121 + 24 = 145
∴ Next three terms are: 97, 121, 145.