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in Statistics by (57.2k points)

Fit a straight line to the following time series, show the trend line on a graph

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Let x and y be the year and values The Straight line equation is 

y = a + bx

Normal equations are –

na + bΣx = Σy ………… (1)

aΣx + bΣx2 = Σxy ………….(2)

Here x̄ = 1992

From (1) 7a + b.O = 3106

∴ a = 443.71

From (2) a.O + b.28 = 2045

∴ b= 73.04

∴ The fitted straight line trend equation is

ŷ = 443.71 + 73.04x

Trend value (ŷ) for 1989; Here x = -3

∴ ŷ1989 = 443.71 + 73.04 (-3) = 443.71 – 219.12

ŷ89 = 224.50

Trend value for 1990 ; Here x = -2

ŷ90 = 443.71 + 73.04(-2) = 297.63

Similarly all remaining trend values can be obtained by substituting 

x = -1,0,1,2 and 3 Straight line trend:

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