Diameter, d = 35mm θ = \(\frac{360^o}{10}\) = 36°
Radius, r = \(\frac{35}{2}\)mm
(i) Length of the silver wire required :
Length of the wire used in making 5 diameter + Circumference of
Silver, wire required.
(ii) Area of each sector of the brooch = ?
Diameter of the brooch, d = 35 mm
Radius, r = \(\frac{35}{2}\)mm
Angle at the centre, θ = \(\frac{360^o}{10}\) = 36°
The Area of each sector of the Brooch:
