Given as
[(1 + i)/(1 - i)]3 – [(1 - i)/(1 + i)]3 = x + iy
Now let us rationalize the denominator, we get

i3–(-i)3 = x + iy
2i3 = x + iy
2i2.i = x + iy
2(-1)I = x + iy
-2i = x + iy
By equating real and imaginary parts on both sides we get
x = 0 and y = -2
Thus, the values of x and y are 0 and -2.