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Find the zero of the polynomial in each of the following cases : 

(i) p(x) = x + 5 

(ii) p(x) = x – 5 

(iii) p(x) = 2x + 5 

(iv) p(x) = 3x – 2 

(v) p(x) = 3x 

(vi) p(x) = ax, a ≠ 0 

(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.

1 Answer

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(i) p(x) = x + 5 

Let p(x) =0, then, 

p(x) = x + 5 = 0 

x = 0 – 5 

∴ x = -5 

-5 is zero of 

p(x). 

(ii) p(x) = x – 5 

If p(x) = 0, then 

p(x) = x – 5 = 0 

x = 0 + 5 

∴ x = 5 

5 is the zero of p(x). 

(iii) p(x) = 2x + 5 

If p(x)= 0, then 

p(x) = 2x + 5 = 0 

2x = – 5 

∴ x = \(\frac{-5}{2}\)

\(\frac{-5}{2}\) is the zero of p(x). 

(iv) p(x) = 3x – 2 

If p(x)= 0, then 

p(x) = 3x – 2 = 0 

3x = 2 

∴ x = \(\frac{2}{3}\)

\(\frac{2}{3}\) is the zero of p(x). 

(v) p(x) = 3x 

If p(x) = 0, then 

p(x) = 3x = 0 

∴ x = \(\frac{0}{3}\)

\(\frac{0}{3}\) is the zero of p(x) 

(vi) p(x) = ax, a ≠ 0 

If p(x)= 0, then 

p(x) = ax = 0 

∴ x = \(\frac{0}{a}\)

∴ x = ∞(infinity) 

∞ is the zero of p(x). 

(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers 

If p(x)= 0, then 

p(x) = cx + d = 0 

cx = 0 – d cx = -d 

∴ x = - \(\frac{d}{c}\)

is the zero of p(x).

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