Construction of a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm
Steps of Construction :
1. Draw BC = 7 cm line segment.
2. Construct ∠B = 75° and produce it upto Bx.
3. With B as centre draw an arc BD = 13 cm such that it intersects Bx at D.
4. Construct PQ which is the perpendicular bisector of BD.
5. PQ intersects BD at A.
6. Join AC.
7. Now ∆ABC, with measurement AB + AC = 13 cm, and ∠B = 75°, BC = 7 cm is constructed.
