Question

A solenoid of length 1.0 m has 100 turns and as radius 1 cm. 5 A current is flowing in the solenoid. Calculate the axial magnetic field. If an electron moves along its axis with the velocity 10⁴ m/s, then how much force will it experience?

Answer 1

Length of solenoid l - 1.0 m
Radius of solenoid = 1 cm = 10 m, flowing current I = 5 A, Number of turns N = 100
Axial magnetic field in solenoid
B = \(\mu_{0} \frac{N}{l} I\)
B = 4π × 10^-7 × \(\frac{100}{1.0}\) × 5
B = 4 × 3.14 × 5 × 10^-5
B = 6.28 × 10^-3 T along axial direction
If electron moves with velocity 104 m/s along its axis, then the angle between magnetic field and velocity will be O.
From, F = qvBsinθ (θ = 0°)