Question

An inductor L = 200 mH, a capacitor C = 500 µ.F and a resistance R = 100 Ω are connected in series through an ac source of 100 V. Determine :
(i) frequency at which the power factor of the circuit is 1.
(ii) peak value of current at this frequency
(iii) quality factor.

Answer 1

Inductance (L) = 200mH = 200 × 10^-3 H
Capacitance (C) = 500µF = 500 × 10^-6 F
Resistance (R) = 100 Ω
Potential of source (V) = 100 V
(i) Power factor is unit then: