Question

The magnetic field due to the earth has a horizontal component of 26μT at a place where the dip is 60°. Find the vertical component and the magnitude of the field.

Answer 1

δ(dip) = 60°

B_H = Bcos 60°

=> B = 52 × 10^–6 = 52μT

B_V = Bsinδ = 52 × 10^–6√3/2  = 44.98μT ≈ 45μT