Given that, ∠1 = 120° and ∠2 = 100°
From the figure ∠1 and ∠5 is a linear pair
∠1 + ∠5 = 180°
∠5 = 180° – 120°
∠5 = 60°
Therefore, ∠5 = 60°
∠2 and ∠6 are corresponding angles
∠2 = ∠6 = 100°
Therefore, ∠6 = 100°
∠6 and ∠3 a linear pair
∠6 + ∠3 = 180°
∠3 = 180° – 100°
∠3 = 80°
Therefore, ∠3 = 80°
By, angles of sum property
∠3 + ∠5 + ∠4 = 180°
∠4 = 180° – 80° – 60°
∠4 = 40°
Therefore, ∠4 = 40°