Question

Draw ∆ABC in which ∠Q = 80°, ∠R = 55° and QR = 4.5 cm. Draw the perpendicular bisector of side QR.

Answer 1

Steps of construction:

1. Draw a line segment QR = 4.5 cm.

2. Draw ∠RQX = 80° and ∠QRY = 55°.

3. Let QX and RY intersect at P so that PQR is the required triangle.

4. With Q as center and radius more than 2.25 cm, draw arcs on either sides of QR.

5. With R as center and radius more than 2.25 cm, draw arcs intersecting the previous arcs at M and N.

6. Join MN

7. MN is the required perpendicular bisector of QR.