Let the atoms N in cep = x
No of tetrahedral voids = 2x
As \(\frac { 1 }{ 3 }\) rd of the tetrahedral voids are occupied by atoms M,
Hence, no. of atoms of M = \(\frac { 2x }{ 3 }\)
Ratio of M:N = 20 : \(\frac { 2x }{ 3 }\) = 2:3
Hence formula of compound is M2 N3