Length of the hour hand is 4 cm, which describes the radius of the path inscribed by the hour hand.
Length of the minute hand is 6 cm, which describes the radius of the path inscribed by the minute hand.
The circumference of the path inscribed by the hour hand = 2 π r
C = 2 × (22/7) × 4
C = 176/7 cm
The hour hand makes 2 revolutions in one day.
Therefore distance covered by the hour hand in 2 days = (176/7) × 2 × 2
= 100.57 cm
The distance covered by the minute hand in 1 revolution = 2 π r
C = 2 × (22/7) × 6
C = 264/7
As we know, the minute hand makes 1 revolution in one hour.
In 1 day, it makes 24 revolutions.
In 2 days, it makes 2 × 24 revolutions.
The distance covered by the minute hand in 2 days = 2 × 24 × (264/7)
= 12672/7
= 1810.28 cm
The sum of the distances travelled by the hour and minute hands in 2 days = 1810.28 + 100.57
= 1910.85 cm
