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+1 vote
2.9k views
in Chemical Kinetics by (57.3k points)

A reaction is of first order with respect to A and second order with respect to B.
(i) Write differential rate equation.
(ii) How is the rate affected when the concentration of B is trippled?
(iii) How is the rate affected when the concentration of both A and B is doubled.

1 Answer

+1 vote
by (61.2k points)
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Best answer

(i) Rate of reaction
\(\frac { dx }{ dt } \) = k[A] [B]2

(ii) Let[A] = a, [B] = b
If [B] is increases three times
[B] = 3b
then,
rate = k[A] [B]2
rate1 = k × a × b2          ….(1)
rate2 = k x a x (3b)2        …(2)
from eq (1) and (2)

(rate)2 = 9 x (rate)1
The rate becomes nine times.

(iii) (rate) = k[A] [B]2
(rate)1 = k x a x b2
(rate)2 = k x (2a) x (2b)2

(rate)2 = 8 (rate)1
The rate becomes eight times.

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