(i) Rate of reaction
\(\frac { dx }{ dt } \) = k[A] [B]2
(ii) Let[A] = a, [B] = b
If [B] is increases three times
[B] = 3b
then,
rate = k[A] [B]2
rate1 = k × a × b2 ….(1)
rate2 = k x a x (3b)2 …(2)
from eq (1) and (2)
(rate)2 = 9 x (rate)1
The rate becomes nine times.
(iii) (rate) = k[A] [B]2
(rate)1 = k x a x b2
(rate)2 = k x (2a) x (2b)2
(rate)2 = 8 (rate)1
The rate becomes eight times.