Question

An inductor-coil, a capacitor and an AC source of rms voltage 24V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0A is observed. If this inductor coil is connected to a battery of emf 12V and internal resistance 4.0Ω, what will be the current?

Answer 1

E_rms = 24V

r = 4Ω, I_rms = 6A

R = E/I = 24/6 = 4Ω

Internal Resistance = 4Ω

Hence net resistance = 4 + 4 = 8Ω

∴ Current = 12/8 = 1.5A