Solution:
Given charges: +e and +9e
Let the third chare q be placed at a distance x from e and hence its distance from 9e is 16-x cm
For the system to remain in equilibrium,
F1 = F2
Therefore,
F1 = K(e q)/x2
F2 = K(9e)/(16-x)2
Equating F1 and F2 , we get,
9/x2 = 1/(16-x)2
Taking square root on both sides:
3/x = 1/(16-x)
Solving for x, we get,
x = 12cm
Hence, the charge q should be placed at 12 cm from +9e.