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What does phenol form by reaction with the in the presence of NaOH or KOH?

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When phenol reacts with chloroform in the presence of bases (NaOH/ KOH) an aldehyde group (-CHO) gets introduced in the ring at a position ortho to the phenol group and salicylaldehyde is formed. This reaction is called the Reimer-Tiemann reaction.

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