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An alkali metal A gives a compound B (molecular mass = 40) on reacting with water.

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An alkali metal A gives a compound B (molecular mass = 40) on reacting with water. The compound B gives a soluble compound C on treatment with aluminium oxide. Identify A, B, and C and give the reaction involved.

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  • A is sodium and B is Sodium Hydroxide. 
  • Because molecular mass of NaOH is 40. 
  • So C is Sodium Aluminate. 

Al2O3 + 2NaOH → 2NaAlO2 + H2O

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