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Arrange the following in increasing order of oxidation states of Mn, K2MnO4 , MnO2 , KMnO4

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Oxidation state of Mn in K2MnO4
1(2) + x + 4 (-2) = 0
2 + x – 8 = 0
x = 8 – 2
x = +6
Oxidation state of Mn in MnO2
x + 2 (-2) =0
x – 4 = 0
x= +4
Oxidation state of Mn in KMnO4
1 + x + 4 (-2) = 0
1 + x – 8 = 0
x – 7 = 0
x = + 7
∴ Increasing order of oxidation states of Mn,
MnO2 < K2MnO4 < KMnO4

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