Question

2KI + Cl₂ → 2KCl + I₂ , Identify the reducing agent in the reaction.

Answer 1

2KI + Cl₂ ➝ 2KCl + I₂
Oxidation state of of I in KI ⇒ 1 + x = 0
x = -1
Oxidation state of I in I₂ = 0
Oxidation state of Cl in Cl₂ = 0
Oxidation state of Cl in KCl ⇒ 1 + x = 0
x = -1

Since, in this reaction Cl₂ is reduced to KCl which is due to KI So, KI is reducing agent in the reaction.